a = V-V0)/t = (60-0)/7.2 = 8.33 m/s^2.
F = M*a
The acceleration of gravity is 9.8 m/s2 . What is the magnitude of the total force on a(n) 85 kg driver by the dragster he operates as it accelerates horizontally along a straight
line from rest to 60 m/s in 7.2 s? Answer in units of kN
So far I have (60-0)/7.2=8.34 but I got it wrong
Please help!!
1 answer
2 answers