a = change in v/change in time
a = 60/8.2 = 7.32 horizontal
so horizontal force = 94*7.32 = 688 N
vertical force up = weight = m g = 94*9.8 = 921 N
net force = sqrt(921^2 + 688^2)
The acceleration of gravity is 9.8 m/s2 . What is the magnitude of the total force on a(n) 94 kg driver by the dragster he operates as it accelerates horizontally along a straight
line from rest to 60 m/s in 8.2 s? Answer in units of kN
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