Vo = 0
V = 41 m/s.
t = 5.3 s.
M = 87 kg
a = (V-Vo)/t
Fx = M*a
Fy = M*g
F = Sqrt(Fx^2+Fy^2) = Total force.
The acceleration of gravity is 9.8 m/s
2
.
What is the magnitude of the total force on
a(n) 87 kg driver by the dragster he operates
as it accelerates horizontally along a straight
line from rest to 41 m/s in 5.3 s?
Answer in units of kN
1 answer