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The 1st term of an AP is 6 and the 5th term is 18.find the number of term in the series having a sum of 162?

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d = (18-6)/4 = 3
n/2 (2*6 + 3(n-1)) = 162
n = 9

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The 4th term of an AP is 6.if the sum of the 5th term is 18.find the number of term in the series hearing a sum of 162.

N=9

9

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