a ar^1 ar^2 ar^3 ----- ar^(n-1)
ar^2 = 9a
so a = 3
a r = (1/24) a r^4
r = (1/24) r^4
r^3 = 24 = 8*3 remember this
so
r = 2 *3^(1/3)
fourth = a r^3
= 3 *24 = 72
the 3rd term of a geometric progression is nine times the 1st term.if the 2nd term is one-twenty fourth the 5th term.find the 4th term.(my solution so far).ar^2=9a r=sqr of 9 r=3.help me find the 1st term
1 answer
1 answer