The 3rd term of a geometric progression is nine times the first term.if the second term is one-twenty fourth the 5th term.find the 4th term. solution ar^2=9a r=sqr of 9 r=3.pls help me on how to get the first term(a)

Answer 1

ar^2 = 9a
so, r = ±3

Now we have a problem. We know that r=3, so the 5th term must be 27 times the 2nd term, regardless of the value of a.

And, as you say, there is no way to determine a from the information given so far.

You sure it's not 24 less than the 5th term?

Answer 2

Pls show work in details.