Test the claim that the mean body temperature is less than 98.6 using a= 0.05. Assume a smaple of 16 yilded a mean of 98.2 with a standard deviation of 0.6

1 answer

Z = difference between means/√SE^2

SE = SD/√(n-1) (or just √n)

Look up value in table in back of statistics text labeled something like "areas under normal distribution.

I hope this helps. Thanks for asking.