Listed below are body temperatures for four subjects measured at two different times in a day.

Body Temperature (ยฐ๐น) ๐‘Ž๐‘ก 6 ๐‘Ž๐‘š: 98.0,97.0,98.6,97.4
Body Temperature (ยฐ๐น) ๐‘Ž๐‘ก 6 ๐‘๐‘š: 98.0,97.6,98.8,98.0
Assume the sample data are simple random samples and that the differences have a distribution that is approximately normal. Test the claim that body temperature measured at 6 pm is higher than the body temperature measured at 6 am. Use a 0.10 significance level. Show your work.
a. Give the symbolic null & alternative hypotheses. Use correct notation.
H0: HA:
b. Determine the test statistic (round to 3 decimal places): __________________
c. Determine the p-value (round to 3 decimal places):
d. Result (Circle one & justify): REJECT ๐‘ฏ๐ŸŽ FAIL TO REJECT ๐‘ฏ๐ŸŽ
Reason:
e. State a conclusion within the context of the scenario

Did I solve this correctly?

a. H0: ยตd โ‰ฅ 0
HA: ยตd < 0;
D = Temperature at 6 AM - Temperature at 6 PM

b. -2.333
Sample size = 4
Average = -0.35
Std. Dev = 0.3

Test statistic = (-0.35-0)/0.3/โˆš4=-2.333

c. 0.051
Df = 4-1 = 3
P-value = P(t(3) < -2.333) = 0.051

d. Reject Ho
Reason: The P value of 0.051 is smaller than the significance level of 0.05

e. We reject the null hypothesis due to the data providing enough evidence that the body temperature measured at 6pm is higher than the body temperature measured at 6am.