assume the body temperature of healthy adults distributed with a mean of 98.20F and a standard deviation of 0.62F. If you have a body temperature of 99.00F, what is your percentile score?

Answer 1

Z = (x-mean)/SD

Insert values and solve for Z.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to that Z score.

Answer 2

99.0-98.2/0.62
Answer = 1.29

Is this correct?