Take the second derivative of 2sin2(x) and evaluate it at x=π/3.
So I got the second derivative, -8sin(2x)
How do I solve plug in x=π/3 and solve? Do I use the special triangle?
2 answers
So if I am supposed to use special triangles, would the final answer be -3.64
Your second derivative is correct.
Yes, use your special triangles
especially the 30-60-90 triangle, where sin 60° = √3/2 and sin 120° = √3/2 by the CAST rule
think π/3 ----> 60°
so -8sin(2x) = -8(√3/2) = -4√3 = appr 6.928
how did you get -3.64 ?
Yes, use your special triangles
especially the 30-60-90 triangle, where sin 60° = √3/2 and sin 120° = √3/2 by the CAST rule
think π/3 ----> 60°
so -8sin(2x) = -8(√3/2) = -4√3 = appr 6.928
how did you get -3.64 ?