df/dx = 2 e^y (3 x^2)
= 6 x^2 e^y
df/dy = 2 x^3 (de^y/dy) = 2 x^3 e^y (in other words partial with respect to y is original function)
Evaluate: f(x,y)=2x^3e^y
a) partial derivative with respect to x.
I know that you have to treat y as a constant but I have no idea what to do. I do not understand partial derivatives at all. Please help!!
b) partial derivative with repsect to y.
2 answers
for the first one how did you get (3x^2)?