6-1 = 5
integral Rdt from 1 to 6 = 6 t^3 + 2 t^2 + 3 t at 6 minus at 1
= 1386 - 11 = 1375
1375/5 = 275
R(6) = 675
R(1) = 25
change = 670
change/5 = 134
Suppose the annual revenue for a company between 2000 and 2005 is approximated by
R(t) = 18t^2 + 4t + 3, where t = 0 represents the year 2000.
(a) Find the Average Value of R(t) between t = 1 and t = 6.
(b) Find the Average Rate of Change of R(t) between t = 1 and t = 6.
1 answer
1 answer