Suppose the annual revenue for a company between 2000 and 2005 is approximated by R(t)=18t^2+4t+3, where t=0 represents the year 2000.(a)Find the Average Value of R(t) between t=1and t=6.

Question

(b)Find the Average Rate of Change of R(t) between t=1 and t=6.

Answer 1

averageRevenue*time= int (R(t))dt from t=0 to 6
average Revenue* 6)=int(18t^2+4t+3)dt over interval
=6t^3+2t^2 + 3t over interval= 1296+72+18=
average revenue= 1/6 (1386)=231
check my work.