I assume the 0.0021 is M.
mols KOH = M x L = ?
mols HNO3 = mols KOH (from the coefficients in the equation.)
M HNO3 = mols HNO3/L HNO3. You know mols and L, solve for M.
Suppose that 10.9 mL of HNO3 is neutralized by 83.9 mL of a 0.0021 < solution of KOH in a titration. Calculate the concentration of the HNO3 solution.
Answer in units of M
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