A 25ml solution of 0.5M NaOH is titrated until neutralized into a 50ml sample of HNO3. What was the concentration of the HNO3?
5 answers
What was the concentration of the HNO3?
HNO3 + NaOH ==> NaNO3 + H2O
mols NaOH = M x L = 0.5 z 0.025 = ?
mols HNO3 = mols NaOH since it is 1:1 ratio of acid to base.
Then M HNO3 = mols HNO3/L HNO3 = ?
mols NaOH = M x L = 0.5 z 0.025 = ?
mols HNO3 = mols NaOH since it is 1:1 ratio of acid to base.
Then M HNO3 = mols HNO3/L HNO3 = ?
Please help me
C1=0.5M
V1=(25÷1000=0.025dm^3)
C2=?
V1=(50÷1000=0.05dm^3)
Therefore using ,C1V1=C2V2
C2=((0.5×0.025)÷0.05)
C2=0.25M
V1=(25÷1000=0.025dm^3)
C2=?
V1=(50÷1000=0.05dm^3)
Therefore using ,C1V1=C2V2
C2=((0.5×0.025)÷0.05)
C2=0.25M
The concentration of the HNO3 is 0.25 M.
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