Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$.

Question

Determine $p(x)$ (in expanded form).

Answer 1

john is 30 pounds heavier than peter. their total weight 235 pounds.find johns weight

Answer 2

peter is 30 lbs lighter than john. So,

j + j-30 = 235

Odd; I expected an integer answer...

as for the polynomial, who knows? I see no question there. And LaTex doesn't do well here. And p(x) cannot be monic with real coefficients and have a complex root.

Answer 3

ah, actually I misspoke.

Since 3+2i is also a root, we have

p(x) = (x-(3-2i))(x-(3+2i))(x-a)
= (x^2-6x+13)(x-a)

So, now just solve for a:

p(0) = -13a = -52
a = 4

p(x) = (x^2-6x+13)(x-4) = x^3-10x^2+37x-52

Answer 4

Thanks so much :)

Answer 5

i would like to 1v1 someone in valorant drop your name and tagline

Answer 6

Chunky Kong

Answer 7

yes

Answer 8

I love how this started with math and out of nowhere came a 1v1 request

Answer 9

ur mom