1.
Need four zeros but every complex root comes with its complex conjugate
i so also -i
9+i so also 9-i
(x-3)(x-3)(x- 6i)(x+6i)
multiply that out
I have two questions that I don't understand and need help with.
1. information is given about a polynomial f(x) whose coefficients are real numbers. Find the remaining zerosof f.
degree 4, zeros i;9+i
2. form a polynomial f(x) with real coefficients having the given degree and zeros.
degree 4, zeros 3, multiplicity 2; 6i
f(x)=a(?)
1 answer