Suppose an astronaut drops a feather from 1.1 m above the surface of the moon. If the acceleration due to gravity on the moon is 1.62 m/s^2 downward, how long does it take the feather to hit the Moon's surface?

Answer 1

h=1/2 a t^2 = 1/2 (1.62)t^2=1.1
solve for t