Suppose an astronaut drops a feather from 1.1 m above the surface of the moon. If the acceleration due to gravity on the moon is 1.62 m/s2 downward, how long does it take the feather to hit the Moon's surface?

Answer 1

distance = 1/2 a t^2 ... 1.1 = 1/2 * 1.62 * t^2

solve for t