Question

Solve this log function:

a) log (sqrt(x^2-3x))=0.5
b) log (sqrt(x^2+48x))=1

Answer 1

a) Assuming that you mean log to base 10,
sqrt(x^2-3x) = 10^0.5 = sqrt 10
x^2 -3x = 10
(x-5)(x+2) = 0
x= 5 or -2

Do (b) the same way. First restate it without the log function.
sqrt (x^2 + 48x) = 10
x^2 + 48x = 100
Then solve the quadratic function.

Answer 2

a) Assuming that you mean log to base 10,
sqrt(x^2-3x) = 10^0.5 = sqrt 10
x^2 -3x = 10
(x-5)(x+2) = 0
x= 5 or -2

Do (b) the same way. First restate it without the log function.
sqrt (x^2 + 48x) = 10
Then solve the quadratic that results when you square that.

Answer 3

We seem to have a faulty web server. It took several minutes for my answer to be posted, so I did it again