Question

Solve for the function y.

dy/dx = xe^y, when y(1)=0

I got as far as:
e^-y dy = x dx

But then how do you continue from there?

Answer 1

dy e^-y = x dx

- e^-y = .5 x^2 + c
when x = 1, y = 0
- e^0 = .5 * 1 + c
-1 = .5 + c
c = -1.5
so
e^-y = -.5 x^2 + 1.5