Asked by Kyle
Solve for the function y.
dy/dx = xe^y, when y(1)=0
I got as far as:
e^-y dy = x dx
But then how do you continue from there?
dy/dx = xe^y, when y(1)=0
I got as far as:
e^-y dy = x dx
But then how do you continue from there?
Answers
Answered by
Damon
dy e^-y = x dx
- e^-y = .5 x^2 + c
when x = 1, y = 0
- e^0 = .5 * 1 + c
-1 = .5 + c
c = -1.5
so
e^-y = -.5 x^2 + 1.5
- e^-y = .5 x^2 + c
when x = 1, y = 0
- e^0 = .5 * 1 + c
-1 = .5 + c
c = -1.5
so
e^-y = -.5 x^2 + 1.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.