Question

Solve the function

2(9^x) - 5(3^×) = 12

So what I did So far is changed it into log functions:

2(9^x) = 12
9^x = 6
Log9(6) = x

And then
5(3^x) = 12
3^x = 12/5
Log3(12/5) = x

So then I don't know how to subtract them because they have different bases :/

Answer 1

who are you and why are you using my name?

Answer 2

... my name's also rose? I'm just trying to get math help man

Answer 3

kay

Answer 4

2*(3^2)^x - 5*3^x = 12


2*3^x *3^x - 5*3^x = 12

let z = 3^x

2 z^2 -5 z -12 = 0

z = 4 or -3/2
so
3^x = 4
or
3^x = -1.5

now x log 3 = log 4 etc