Question

Solve the simultaneous equation below 2x_3y=5
_x+2y=_3

Answer 1

using more normal notation, you have
2x-3y = 5
-x+2y = -3

2x - 3y = 5
-2x+4y = -6
Add to eliminate x:
y = -1
Now finish it off

Answer 2

2x_3y=5
_x+2y=_3

Assuming you meant:
2x-3y=5
-x+2y=-3

double the 2nd, then add to the first

2x-3y=5
-2x+4y=-6
y = -1
then
2x-3(-1) = 5
x = 1

Answer 3

Yes