using more normal notation, you have
2x-3y = 5
-x+2y = -3
2x - 3y = 5
-2x+4y = -6
Add to eliminate x:
y = -1
Now finish it off
Solve the simultaneous equation below 2x_3y=5
_x+2y=_3
3 answers
2x_3y=5
_x+2y=_3
Assuming you meant:
2x-3y=5
-x+2y=-3
double the 2nd, then add to the first
2x-3y=5
-2x+4y=-6
y = -1
then
2x-3(-1) = 5
x = 1
_x+2y=_3
Assuming you meant:
2x-3y=5
-x+2y=-3
double the 2nd, then add to the first
2x-3y=5
-2x+4y=-6
y = -1
then
2x-3(-1) = 5
x = 1
Yes