Asked by fardeen
solve the simultaneous equation
2x+2y=7
x^2-4y^2=8
2x+2y=7
x^2-4y^2=8
Answers
Answered by
sanjeet
x^2-4y=8.............(1)
2x+2y=7
or 2x=7-2y
or x=7-2y/2......(2)
from 1&2
(7-2y)^2-4y=8
or 49-28y+4y^2-4y=8
or 4y^2-32y=41
4y(y-32)=41
either 4y=41....(a)
or y-32=41.....(b)
from a
y=41/4=10.25
from b
y=73
so, y=10.25 or 73
2x+2y=7
or 2x=7-2y
or x=7-2y/2......(2)
from 1&2
(7-2y)^2-4y=8
or 49-28y+4y^2-4y=8
or 4y^2-32y=41
4y(y-32)=41
either 4y=41....(a)
or y-32=41.....(b)
from a
y=41/4=10.25
from b
y=73
so, y=10.25 or 73
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