To solve the quadratic equation \( x^2 - 6x - 5 = 0 \) by completing the square, we follow these steps:
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Move the constant term to the other side of the equation: \[ x^2 - 6x = 5 \]
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To complete the square, we need to take half of the coefficient of \( x \), square it, and add it to both sides. The coefficient of \( x \) is -6.
- Half of -6 is -3, and squaring it gives \( (-3)^2 = 9 \).
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Add 9 to both sides: \[ x^2 - 6x + 9 = 5 + 9 \] \[ x^2 - 6x + 9 = 14 \]
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Now, the left side can be factored as a square: \[ (x - 3)^2 = 14 \]
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We can now take the square root of both sides: \[ x - 3 = \pm \sqrt{14} \]
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Solving for \( x \): \[ x = 3 \pm \sqrt{14} \]
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This gives us two solutions: \[ x = 3 + \sqrt{14} \quad \text{and} \quad x = 3 - \sqrt{14} \]
Now, we compute the numerical values of these solutions:
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Calculate \( \sqrt{14} \): \[ \sqrt{14} \approx 3.74 \]
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Therefore, the solutions are: \[ x_1 = 3 + 3.74 \approx 6.74 \] \[ x_2 = 3 - 3.74 \approx -0.74 \]
Finally, rounding to the nearest hundredth, we find:
Form:
The completed square form is: \[ (x - 3)^2 = 14 \]
Solution:
The solutions, rounded to the nearest hundredth, are: \[ \boxed{6.74, -0.74} \]