Asked by Daniel
solve the quadratic equation 2x^4-3x^3-7x^2 12x-4=0
Answers
Answered by
Steve
well, if you meant
2x^4-3x^3-7x^2+12x-4, it is a quartic, but can easily be factored into two quadratic factors.
It is (x^2-4)(2x^2-3x+1)
which are both easily solved.
2x^4-3x^3-7x^2+12x-4, it is a quartic, but can easily be factored into two quadratic factors.
It is (x^2-4)(2x^2-3x+1)
which are both easily solved.
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