Asked by Anonymous
Solve the quadratic equation by completing the square. Verify your answer graphically. (Enter your answers as a comma-separated list.)
16x2 − 24x − 23 = 0
my answer was:
x =16(x−3/4)^2−32
but online website (where i do my assignments that is posted by my teacher), says it is wrong, i just don't understand why.
16x2 − 24x − 23 = 0
my answer was:
x =16(x−3/4)^2−32
but online website (where i do my assignments that is posted by my teacher), says it is wrong, i just don't understand why.
Answers
Answered by
Motorhead
You've completed the square correctly, but the left side of your equation should be 0, not x.
0 =16(x−3/4)^2−32.
Also, there's more work to do. Rearrange the equation to isolate x. This will take about 4 steps.
0 =16(x−3/4)^2−32.
Also, there's more work to do. Rearrange the equation to isolate x. This will take about 4 steps.
Answered by
Bosnian
16 ( x − 3 / 4 )² − 32 = 0
Divide both sides by 16
( x − 3 / 4 )² − 2 = 0
Add 2 to both sides
( x − 3 / 4 )² − 2 + 2 = 0 + 2
( x − 3 / 4 )² = 2
Take the square root of both sides
x − 3 / 4 = ± √2
Add 3 / 4 to both sides
x − 3 / 4 + 3 / 4 = ± √2 + 3 / 4
x = 3 / 4 ± √2
The solutions are:
x = 3 / 4 - √2 and x = 3 / 4 + √2
Divide both sides by 16
( x − 3 / 4 )² − 2 = 0
Add 2 to both sides
( x − 3 / 4 )² − 2 + 2 = 0 + 2
( x − 3 / 4 )² = 2
Take the square root of both sides
x − 3 / 4 = ± √2
Add 3 / 4 to both sides
x − 3 / 4 + 3 / 4 = ± √2 + 3 / 4
x = 3 / 4 ± √2
The solutions are:
x = 3 / 4 - √2 and x = 3 / 4 + √2
Answered by
Anonymous
Thanks Bosnian
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