so the base of the log is 1/3
in general exponentiation is show with the ^ symbol
e.g. x^2 means "x squared"
subscripts are are more difficult but are usually described like you did, as long as they are well defined tutors will be able to figure it out
log1/3 (x^2 + x) - log1/3(x^2 - x) = 2
log1/3 [ (x^2+x)/(x^2-x)] = 2
(x^2+x)/(x^2-x) = (1/3)^2 = 1/9
cross-multiply
9x^2 + 9x = x^2 - x
8x^2 + 10x = 0
x(8x+10) = 0
x = 0 or -5/4 or -1.25
but x = 0 would make both log1/3 expressions undefined
check:
if x= -1.25
we have
log1/3.3125 - log1/32.8125
which is defined
so x = -1.25 or -5/4
solve the following equation
Log1/3(x2+x)-log1/3(x2-x)=2
the 1/3 should be lowered and the (x^2-x) should be higher. Can someone tell me what tools to use to make them like this when posting?
x= ?
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