Asked by kayla
how do i solve these logs?
log1/2 (3x+1)^1/3= -2
3^(x^3)= 9^x
log1/2 (3x+1)^1/3= -2
3^(x^3)= 9^x
Answers
Answered by
Quidditch
For problem 2:
3^(x^3)=9^3
take log of both sides
(x^3)log(3)=(x)log(9)
divide both sides by x
(x^2)log(3)=log(9)
9=3^2
so
(x^2)log(3)=2log(3)
divide both sides by log(3)
x^2=2
x=sqrt(2)
3^(x^3)=9^3
take log of both sides
(x^3)log(3)=(x)log(9)
divide both sides by x
(x^2)log(3)=log(9)
9=3^2
so
(x^2)log(3)=2log(3)
divide both sides by log(3)
x^2=2
x=sqrt(2)
Answered by
Quidditch
The first line above (where the problems was restated) should have been:
3^(x^3)=9^x
The rest of the lines are correct.
3^(x^3)=9^x
The rest of the lines are correct.