solve the following equation Log1/3(x2+x)-log1/3(x2-x)=2

Suppose 45° < 𝜃 < 90°, let 𝑎=log1/2(sin𝜃), b = log1/2(cos𝜃) ,𝑐 = log1/2(tan𝜃), 𝑑 = log1/2(sec𝜃). Order
1. 1 answer
2. asked by Anonymous
3. 148 views
solve the following equationLog1/3(x2+x)-log1/3(x2-x)=2 the 1/3 should be lowered and the (x^2-x) should be higher. Can someone
1. 1 answer
2. asked by Kyrstal
3. 471 views
Rewrite 103=1,000 as a logarithmic equation.(1 point)Responses log10 3=1,000 log10 3=1,000 log1,000 3=10 log1,000 3=10 log10
1. 1 answer
2. asked by hi
3. 70 views
Find value of x for log1/2(x-1)+log1/2(x+1)-log1/√2(7-x)=1
1. 1 answer
2. asked by prashik
3. 831 views
how do i solve these logs?log1/2 (3x+1)^1/3= -2 3^(x^3)= 9^x
1. 2 answers
2. asked by kayla
3. 398 views
how do i solve these logs?log1/2 (3x+1)^1/3= -2 3^(x^3)= 9^x
1. 3 answers
2. asked by kayla
3. 407 views
write the logarithmic equation in exponential form-2=log1/100 ___^----- = 1/100
1. 1 answer
2. 26 views
3 log 2+log 20-log1.
1. 2 answers
2. asked by Anonymous
3. 205 views
3log2 plus log 20 - log1.6
1. 8 answers
2. asked by Cinderella
3. 2,066 views
Why is log1/a(x), a reflection over the x axis?
1. 1 answer
2. asked by Kevin
3. 420 views