Let's solve the equation step by step, following the process you outlined.
Starting with the equation:
\[ \frac{4}{1}(12r - 8) = 6r + 10 \]
Let's simplify the left side using the distributive property:
\[ 4(12r - 8) = 6r + 10 \]
Distributing \(4\):
\[ 48r - 32 = 6r + 10 \]
Next, let's move all \(r\) terms to one side. We can subtract \(6r\) from both sides of the equation:
\[ 48r - 6r - 32 = 10 \]
This simplifies to:
\[ 42r - 32 = 10 \]
Next, to isolate the \(r\) term, we add \(32\) to both sides:
\[ 42r = 10 + 32 \] \[ 42r = 42 \]
Now, divide both sides by \(42\):
\[ r = \frac{42}{42} \] \[ r = 1 \]
Thus, the value of \(r\) is:
\[ \boxed{1} \]