Solve the equation 2sin^2(theta)+3sin(theta)+1=0 for theta.
3 answers
could i just use the quadratic equation on this problem?
let z = sin theta
2 z^2 + 3 z + 1 = 0
(2 z +1)(z+1) = 0
z = -1/2 or z = -1
sin theta = -1/2
theta = 11 pi/6 or 7 pi/6
sin theta = -1
theta = 3 pi/2
2 z^2 + 3 z + 1 = 0
(2 z +1)(z+1) = 0
z = -1/2 or z = -1
sin theta = -1/2
theta = 11 pi/6 or 7 pi/6
sin theta = -1
theta = 3 pi/2
Thank you!!!
1 answer