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Solve the equation 2sin^2(theta)+3sin(theta)+1=0 for
Solve the equation 2sin^2(theta)+3sin(theta)+1=0 for theta.
3 answers
asked by
anonymous
538 views
convert to polar: 2xy=3
A. r=sqrt(3sin theta cos theta) B. r=sqrt[(3sin theta cos theta)/2] C. r=[3/(2sin theta cos theta)]
1 answer
asked by
Sade
562 views
Identify the polar form of the linear equation 4x+3y=10.
x=rcos(theta),y=rsin(theta) 4x+3y=4rcos(theta)+3rsin(theta)=10
2 answers
asked by
Jon
657 views
knowing that 2(theta) can be written as theta + theta, find the expression for sin2(theta) and cos2(theta).
Is it
1 answer
asked by
Steve
526 views
Find circumference of the circle r=2acos theta.
s= Int (0 to 2pi) of Sqrt(4a^2cos^2 theta+4a^2sin^2 theta)d theta =Int (0 to
3 answers
asked by
ms
1,069 views
What values for theta(0 <= theta <= 2Pi) satisfy the equation? 2sin theta * cos theta + sqrt(3) * cos theta = 0 (1 point) pi/2;
1 answer
52 views
1. Show that Sin3 Theta - Cos2 Theta = (1 - Sin Theta)(4Sin^2 Theta + 2Sin Theta - 1).
Without using a calculator, show that
0 answers
asked by
Edwards
576 views
What values for 0 (0 <= theta <= 2pi) satisfy the equation?
2sin theta * cos theta + sqrt(3) * cos theta = 0 (1 point) pi/2
1 answer
71 views
find all solutions on 0 is greater than or equal to theta < 2pi
cos theta= 2sqrt3/3 4-1/2sin theta= (-16+sqrt3)/4 3(sqrt3)= -3cot
2 answers
asked by
bob
601 views
find all solutions on 0 is greater than or equal to theta < 2pi
cos theta= 2sqrt3/3 4-1/2sin theta= (-16+sqrt3)/4 3(sqrt3)= -3cot
0 answers
asked by
satan666
580 views