To solve the inequality \(-2|x - 7| \leq -8\), we first isolate the absolute value expression:
\[ |x - 7| \geq 4 \]
This is achieved by dividing both sides of the inequality by -2, and remember that dividing by a negative number reverses the inequality sign.
Now, we translate the absolute value inequality \(|x - 7| \geq 4\) into two separate inequalities:
- \(x - 7 \geq 4\)
- \(x - 7 \leq -4\)
Now, we solve both inequalities.
- For \(x - 7 \geq 4\):
\[ x \geq 11 \]
- For \(x - 7 \leq -4\):
\[ x \leq 3 \]
Now, we combine these results into interval notation. The solutions are:
- \(x \leq 3\) corresponds to the interval \((- \infty, 3]\)
- \(x \geq 11\) corresponds to the interval \([11, \infty)\)
Thus, the solution in interval notation is:
\[ (-\infty, 3] \cup [11, \infty) \]
So the final answer is:
\[ \text{The solution to } -2|x - 7| \leq -8 \text{ is } \left( (-\infty, 3] \cup [11, \infty) \right). \]