This is a "nasty" problem and it does not simplify easily.
I don't know how you got your quartic equation.
I rewrote it as 6tanx = 1 + 4sinx
then graphed f(x) = 6tanx and
g(x) = 1+ 4sinx
There are two intersection points, one in quadrant I and another in quadrant III.
After a few iterations, I got x= 23.27ยบ to come pretty close.
This is way beyond any highschool level I know, where did you get that question ?
solve for x
6tanx - 4sinx = 1
i tried it but got a quartic formula :S
16sin^4x + 8sin^3x + 37sin^2x - 36 = 0
2 answers
I got the quartic by moving the sin to the right, squaring both sides, then multiplying everything by sin^2 and then changing the cos to sin.
My friend gave me this question, and he got it from his virtual school for gr 12 advanced functions lol.
My friend gave me this question, and he got it from his virtual school for gr 12 advanced functions lol.