Asked by sonia
The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where f(x) =4sinx/4sinx+6cosx
i already got 3/2 for m but i cant seem to find out how to get the value of b?
i already got 3/2 for m but i cant seem to find out how to get the value of b?
Answers
Answered by
drwls
Does f(x) = 4 sinx/(4sinx+6cosx) ?
If so, you need parentheses in the denominator.
You say you want the tangent point to be at a=2. Do you mean x=2? Or x = 2 pi? I don't see how you can get 3/2 for the slope if the equation involves the sin and cos of 2.
If you have the correct slope m, then you can get b by requiring that the value of y = mx + b be the same at the value of f(x) at at the point of contact.
If so, you need parentheses in the denominator.
You say you want the tangent point to be at a=2. Do you mean x=2? Or x = 2 pi? I don't see how you can get 3/2 for the slope if the equation involves the sin and cos of 2.
If you have the correct slope m, then you can get b by requiring that the value of y = mx + b be the same at the value of f(x) at at the point of contact.
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