Asked by Patricia

ind an equation of the tangent line to the curve at the given point.
y = sin 6x + sin2 6x, (0, 0)
Answered by Steve
at any x the slope is y' = 6 cos6x + 12 sin6x cos6x

y'(0) = 6

so, the line through (0,0) with slope 6 is y=6x
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