that is it, so x+1=x (log2/log3)
x(1-log2/log3)=-1
solve for x
Solve for x:
3^(x+1)=2^x
This is what I have so far...
(x+1)log3 = xlog2
...and now I'm stuck. Help plz? Thanks!
2 answers
expand the left side ...
xlog3 + log3 = xlog2
xlog3 - xlog2 = -log3
x(log3-log2) = -log3
x = -log3/(log3 - log2)
I got x = appr. - 2.7095
check:
3^(-1.7095) = .15288
2^-2.7095 = .15288 , Ok!
xlog3 + log3 = xlog2
xlog3 - xlog2 = -log3
x(log3-log2) = -log3
x = -log3/(log3 - log2)
I got x = appr. - 2.7095
check:
3^(-1.7095) = .15288
2^-2.7095 = .15288 , Ok!
2 answers