if logs are the same, the arguments are the same, so
x-16 = 9x
x = -2
But, log(x) is not defined for x<0, regardless of the base
if you mean the entire exponents is 1+ln(7), then
e^(1+ln(7)) = e^1 * e^ln(7) = 7e
by definition, e^ln(n) = n
Please help, I need help on these two problems.
Solve the equation.
log3(x − 16) = log3(9x)
e^1 + ln(7)
It appears on the homework that the ln(7) is written like this ^ln(7) but I am still stuck on it.
Thanks!
2 answers
Log3 15