Please help, I need help on these two problems.

Solve the equation.
log3(x − 16) = log3(9x)

e^1 + ln(7)

It appears on the homework that the ln(7) is written like this ^ln(7) but I am still stuck on it.

Thanks!

2 answers

if logs are the same, the arguments are the same, so

x-16 = 9x
x = -2
But, log(x) is not defined for x<0, regardless of the base

if you mean the entire exponents is 1+ln(7), then

e^(1+ln(7)) = e^1 * e^ln(7) = 7e

by definition, e^ln(n) = n
Log3 15
Similar Questions
    1. answers icon 2 answers
  1. Solve the equation.2log3 y = log3 4+ log3 (y+8) Here's what ive got take out the logs and say y^2= 4+ y +8 which simplifies to
    1. answers icon 2 answers
  2. Can someone explain how to figure out these types of problems?Solve log3 (x - 4) > 2. Evaluate log7 49. If log5 4 ≈ .8614 and
    1. answers icon 1 answer
  3. 1) Solve the equation exactly for x:log3 x - log3(x-3) = 2 I got 1 as an answer. Is this correct? 2) Find the cotangent of the
    1. answers icon 1 answer
more similar questions