log3x +log3(x+7)=log3(x)(x+7)
then take the antilog of each side.
x(x+7)=3^k then, this will be a quadratic equation.
1) Solve for x in terms of k:
log3(x) + log3(x+7) = k; 3 is the base
2) e^(x+5) = e^(x) + 6, solve for x.
Please help, I have no idea how to do these and I've tried several times!
1 answer