since 3x^2+11x-20 = (3x-4)(x+5) you have
log(3x-4)+log(x+5)-log(3x-4) = log(x+5)
log3(27) = 3
log(18) = log(9) + log(2)
So, you have
1/6 (3) + 2 + log3(2) - log3(2) = 5/2
625 = 5^4, so you have
log5(5^(4/3)) = 4/3
surely you meant loga w. If so, you have
log_a(x^6 y^3 z^4 w^3)
Express the following as a logarithm and simplify.
1. log(3x^2 + 11x - 20) - log(3x - 4)
2. 1/6 log3 27 + log3 18 - log3 2
3. log5 cube root of 625
4. 2loga x^3 + 3loga y + 4loga z - 3logz w
1 answer
1 answer