To solve the equation \( 3(-3b + 10) = -6b - 10 + 5b \), we will first simplify both sides of the equation.
Starting with the left side:
\[ 3(-3b + 10) = 3 \cdot -3b + 3 \cdot 10 = -9b + 30 \]
Now the equation looks like this:
\[ -9b + 30 = -6b - 10 + 5b \]
Next, we simplify the right side:
\[ -6b + 5b = -b \]
So now the equation becomes:
\[ -9b + 30 = -b - 10 \]
Next, we will add \( 9b \) to both sides to eliminate \( -9b \) on the left:
\[ 30 = -b + 9b - 10 \]
This simplifies to:
\[ 30 = 8b - 10 \]
Now, add \( 10 \) to both sides:
\[ 30 + 10 = 8b \]
This simplifies to:
\[ 40 = 8b \]
Next, divide both sides by \( 8 \):
\[ b = \frac{40}{8} \]
This simplifies to:
\[ b = 5 \]
Thus, the solution for \( b \) is:
\[ \boxed{5} \]
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