Solve and please explain how you arrived at your ans: square of 3x-1=2
3 answers
are you asking to solve for (3x -1 ) squared= 2 ?
if so then just use foil or box technique to multiply (3x -1) against itself to get
9x^2 -6x +1 = 2
subtract 2 from both side to get
9x^2 - 6x -1 = 0
and then use quadratic formula to solve for x because i don't think you can factor this unless missing something
9x^2 -6x +1 = 2
subtract 2 from both side to get
9x^2 - 6x -1 = 0
and then use quadratic formula to solve for x because i don't think you can factor this unless missing something
or, with less work,
(3x-1)^2 = 2
3x-1 = ±√2
3x = 1±√2
x = (1±√2)/3
(3x-1)^2 = 2
3x-1 = ±√2
3x = 1±√2
x = (1±√2)/3
1 answer