Asked by Kadesha

Solve and please explain how you arrived at your ans: square of 3x-1=2
Answered by visoth
are you asking to solve for (3x -1 ) squared= 2 ?
Answered by visoth
if so then just use foil or box technique to multiply (3x -1) against itself to get

9x^2 -6x +1 = 2

subtract 2 from both side to get

9x^2 - 6x -1 = 0

and then use quadratic formula to solve for x because i don't think you can factor this unless missing something
Answered by Steve
or, with less work,

(3x-1)^2 = 2
3x-1 = ±√2
3x = 1±√2
x = (1±√2)/3
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