solve 16x^2 - 81=0

Answer 1

To solve the equation 16x^2 - 81 = 0, we can first add 81 to both sides of the equation to get:

16x^2 = 81

Next, we can divide both sides by 16 to isolate x^2:

x^2 = 81/16

Taking the square root of both sides, we get:

x = ±√(81/16)

x = ±√(9/4)

x = ±(3/2)

Therefore, the solutions to the equation are x = 3/2 or x = -3/2.

Answer 2

square root 70 is approximately equal to ___.

Answer 3

The square root of 70 is approximately equal to:
√70 ≈ 8.37

Answer 4

what are the prime factors of 90?

Answer 5

To find the prime factors of 90, we can start by dividing 90 by the smallest prime number, 2:

90 ÷ 2 = 45

Then, 45 is not a prime number, so we divide it by 3, which is the next smallest prime number:

45 ÷ 3 = 15

Next, we divide 15 by 3 again:

15 ÷ 3 = 5

Finally, we divide 5, which is a prime number, by itself:

5 ÷ 5 = 1

So, the prime factors of 90 are: 2 x 3 x 3 x 5, which can be written as 2 x 3^2 x 5.

Answer 6

if the replacement set is the set of integers, find the solution set for the inequality:
x - 9 < -15

Answer 7

To solve the inequality x - 9 < -15, we can first add 9 to both sides of the inequality:

x - 9 + 9 < -15 + 9
x < -6

So, the solution set for the inequality x - 9 < -15 when the replacement set is the set of integers is all integers x such that x < -6. Written in set notation, the solution set is:

{x | x < -6}