sinA/1+cosA + 1+cosA/sinA

1 answer

I will assume you mean
sinA/(1+cosA) + (1+cosA)/sinA
= (sin^2 A + (1 + cos A)^2 )/(sinA(1+cosA))
= (sin^2 A + 1 + 2cosA + cos^2 A)/(sinA(1+cosA))
= (2 + 2cosA)/(sinA(1+cosA))
= 2(1 + cosA)/(sinA(1+cosA))
= 2/sinA or 2cscA

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