Simplify

Question

A.1/root a +2
b.root 18/25
c.root a x cubed root a
d.root x + 2 root y/root x-2 root y
e.root5 x root72 /root 3

Answer 1

you really have to use brackets to establish the order of operations you want.

e.g. in #1,
the way you typed it it would be (1/√a) + 2
but I sense you meant 1/(√a + 2)

in b) did you mean √(18/25) ?

etc

Answer 2

e) is the only one not ambiguous,

√5*(√72/√3)
= √5*√24
= √120
= 2√30

Also your use of x is not consistent
in c) you are using x as a multiplier, in d) you are using x as a variable
if you have to show a multiplication signs, either use brackets such as (2)(3) or the * sign,
eg 2*3

Answer 3

Key
*=multiplication
|= square root because I don't have the correct symbol

A.1/|a +2
b.|18/25
c.|a * 3|a
d.|x + 2|y / |x - 2|y

Please help

Answer 4

Ok, so you are saying
a. 1/√a + 2
= (1/√a)(√a/√a) + 2
= (√a)/a + 2

b. still not clear if you meant
√(18/25) or √18 /25
for first interpretation: = 3√2/5
for 2nd interpretation: = 3√2 /25

c). I will take the original as
squareroot(a) * cuberoot(a)
= a^(1/2) * a^(1/3)
= a^(1/2+1/3)
= a^(5/6) or (sixthroot(a))^5

d) again, I will read it as

y√(x+2)/(y√(x-2) )
= √(x+2)/√(x-2)
= √(x+2)/√(x-2) * √(x-2)/√(x-2)
= √((x+2)(x-2) )/(x-2)
= √(x^2 - 4)/(x-2)

the second line of √(x+2)/√(x-2) should be accepted as simplified as well, unless it wanted the denominator rationalized

Answer 5

Thanks alot reiny