Asked by Bettina
                Simplify
A.1/root a +2
b.root 18/25
c.root a x cubed root a
d.root x + 2 root y/root x-2 root y
e.root5 x root72 /root 3
            
        A.1/root a +2
b.root 18/25
c.root a x cubed root a
d.root x + 2 root y/root x-2 root y
e.root5 x root72 /root 3
Answers
                    Answered by
            Reiny
            
    you really have to use brackets to establish the order of operations you want.
e.g. in #1,
the way you typed it it would be (1/√a) + 2
but I sense you meant 1/(√a + 2)
in b) did you mean √(18/25) ?
etc
    
e.g. in #1,
the way you typed it it would be (1/√a) + 2
but I sense you meant 1/(√a + 2)
in b) did you mean √(18/25) ?
etc
                    Answered by
            Reiny
            
    e) is the only one not ambiguous,
√5*(√72/√3)
= √5*√24
= √120
= 2√30
Also your use of x is not consistent
in c) you are using x as a multiplier, in d) you are using x as a variable
if you have to show a multiplication signs, either use brackets such as (2)(3) or the * sign,
eg 2*3
    
√5*(√72/√3)
= √5*√24
= √120
= 2√30
Also your use of x is not consistent
in c) you are using x as a multiplier, in d) you are using x as a variable
if you have to show a multiplication signs, either use brackets such as (2)(3) or the * sign,
eg 2*3
                    Answered by
            Bettina
            
    Key
*=multiplication
|= square root because I don't have the correct symbol
A.1/|a +2
b.|18/25
c.|a * 3|a
d.|x + 2|y / |x - 2|y
Please help
    
*=multiplication
|= square root because I don't have the correct symbol
A.1/|a +2
b.|18/25
c.|a * 3|a
d.|x + 2|y / |x - 2|y
Please help
                    Answered by
            Reiny
            
    Ok, so you are saying
a. 1/√a + 2
= (1/√a)(√a/√a) + 2
= (√a)/a + 2
b. still not clear if you meant
√(18/25) or √18 /25
for first interpretation: = 3√2/5
for 2nd interpretation: = 3√2 /25
c). I will take the original as
squareroot(a) * cuberoot(a)
= a^(1/2) * a^(1/3)
= a^(1/2+1/3)
= a^(5/6) or (sixthroot(a))^5
d) again, I will read it as
y√(x+2)/(y√(x-2) )
= √(x+2)/√(x-2)
= √(x+2)/√(x-2) * √(x-2)/√(x-2)
= √((x+2)(x-2) )/(x-2)
= √(x^2 - 4)/(x-2)
the second line of √(x+2)/√(x-2) should be accepted as simplified as well, unless it wanted the denominator rationalized
    
a. 1/√a + 2
= (1/√a)(√a/√a) + 2
= (√a)/a + 2
b. still not clear if you meant
√(18/25) or √18 /25
for first interpretation: = 3√2/5
for 2nd interpretation: = 3√2 /25
c). I will take the original as
squareroot(a) * cuberoot(a)
= a^(1/2) * a^(1/3)
= a^(1/2+1/3)
= a^(5/6) or (sixthroot(a))^5
d) again, I will read it as
y√(x+2)/(y√(x-2) )
= √(x+2)/√(x-2)
= √(x+2)/√(x-2) * √(x-2)/√(x-2)
= √((x+2)(x-2) )/(x-2)
= √(x^2 - 4)/(x-2)
the second line of √(x+2)/√(x-2) should be accepted as simplified as well, unless it wanted the denominator rationalized
                    Answered by
            Bettina
            
    Thanks alot reiny
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.