Asked by Scholastica
Simplify,root 3xy^3 root 2x^2y divided by root 6x^3y^4
x>0,y>0
x>0,y>0
Answers
Answered by
Bosnian
sqrt ( 3 x * y ^ 3 )* sqrt ( 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =
sqrt ( 3 x * y ^ 3 * 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =
sqrt ( 6 x ^ 3 y ^ 4 ) / sqrt ( 6 x ^ 3 y ^ 4 ) = 1
sqrt ( 3 x * y ^ 3 * 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =
sqrt ( 6 x ^ 3 y ^ 4 ) / sqrt ( 6 x ^ 3 y ^ 4 ) = 1
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