I am almost sure you meant:
6/(√3 + 2)
then ...
= 6/(√3 + 2) * (√3-2)/(√3-2)
= (6√3 - 12)/(3-4)
= 12 - 6√3 , you are correct
btw, those brackets I put in are essential, or else you would have two terms
Simplify
6/sq root 3 +2
My answer is 12 - 6 sq root 3
3 answers
If you mean
(6/sqrt(3)) + 2
then, first, multiply the term with the radical (squareroot sign, cuberoot sign, etc.) with radical term, in numerator and denominator:
(6/sqrt(3)) * (sqrt(3)/sqrt(3)) + 2
Then simplify,
(6*sqrt(3) / sqrt(3)^2) + 2
6*sqrt(3) / 3 + 2
2*sqrt(3) + 2
hope this helps~ `u`
(6/sqrt(3)) + 2
then, first, multiply the term with the radical (squareroot sign, cuberoot sign, etc.) with radical term, in numerator and denominator:
(6/sqrt(3)) * (sqrt(3)/sqrt(3)) + 2
Then simplify,
(6*sqrt(3) / sqrt(3)^2) + 2
6*sqrt(3) / 3 + 2
2*sqrt(3) + 2
hope this helps~ `u`
Reiny still correct bby
0 answers