show that 2logx(a+b)= 2logx a+logx(1+ 2b/a + b^2/a^2)

Answer 1

2log(a+b) = log (a+b)^2 = log (a^2+2ab+b^2)

2log a + log(1 + 2b/a + b^2/a^2)
= log (a^2 (a^2+2ab+b^2)/a^2)

looks the same to me