do you have an answer?
two answers have been posted
Make into one log function:
2logx-log4-log3+logx
2 answers
2*log(x)-log(4)-log(3)+log(x)=2logx+logx-log4-log3
=3*log(x)-[log(4)+log(3)]
log(x^n)=n*log(x)
3*log(x)=log(x^3)
log(a)+log(b)=log(a*b)
log(4)+log(3)=log(4*3)=log(12)
log(a)-log(b)=log(a/b)
3*log(x)-[log(4)+log(3)]=log[(x^3)/12]
=3*log(x)-[log(4)+log(3)]
log(x^n)=n*log(x)
3*log(x)=log(x^3)
log(a)+log(b)=log(a*b)
log(4)+log(3)=log(4*3)=log(12)
log(a)-log(b)=log(a/b)
3*log(x)-[log(4)+log(3)]=log[(x^3)/12]