Make into one log function:

2logx-log4-log3+logx

2 answers

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2*log(x)-log(4)-log(3)+log(x)=2logx+logx-log4-log3
=3*log(x)-[log(4)+log(3)]

log(x^n)=n*log(x)
3*log(x)=log(x^3)

log(a)+log(b)=log(a*b)
log(4)+log(3)=log(4*3)=log(12)

log(a)-log(b)=log(a/b)

3*log(x)-[log(4)+log(3)]=log[(x^3)/12]